5у-y²=6
5y-y²-6=0
-5y+y²+6=0
y²-5y+6=0
y²-2y-3y+6=0
y*(y-2)-3(y-2)=0
(y-2)*(y-3)=0
y-2=0
y-3=0
y1=2
y2=3
Ответ: y1=2, y2=3
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5у-y²=6
5y-y²-6=0
-5y+y²+6=0
y²-5y+6=0
y²-2y-3y+6=0
y*(y-2)-3(y-2)=0
(y-2)*(y-3)=0
y-2=0
y-3=0
y1=2
y2=3
Ответ: y1=2, y2=3