[tex]\displaystyle\bf\\ + \left \{ {{5x - 2y = 0} \atop {x +2 y = 12 }} \right. \\ \\ 5x + x = 0 + 12 \\ 6x = 12 \\ x = 12 \div 6 \\ x = 2 \\ \\ 2 +2 y = 12 \\ 2y =1 2 - 2\\ 2y = 10 \\ y = 10 \div 2 \\ y = 5[/tex]
Ответ: ( 2 ; 5 )
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[tex]\displaystyle\bf\\ + \left \{ {{5x - 2y = 0} \atop {x +2 y = 12 }} \right. \\ \\ 5x + x = 0 + 12 \\ 6x = 12 \\ x = 12 \div 6 \\ x = 2 \\ \\ 2 +2 y = 12 \\ 2y =1 2 - 2\\ 2y = 10 \\ y = 10 \div 2 \\ y = 5[/tex]
Ответ: ( 2 ; 5 )