Пошаговое объяснение:

sin(x-π/6)=0

x-π/6=0

x-π/6=π

x-π/6=0+2kπ,k∈z

x-π/6=π+2kπ,k∈z

x=π/6+2kπ,k∈z

x=π+π/6+2kπ,k∈z

x=π/6+2kπ,k∈z

x=7π/6+2kπ,k∈z

ответ: π/6+2kπ,k∈z