[tex] \frac{10}{8 + x} - \frac{2 - x}{8 + x} = \frac{10 - 2 + x}{8 + x} = \frac{8 + x}{8 + x} = 1 [/tex]
[tex] \frac{x + 2}{x - 5} + \frac{x - 12}{x - 5} = \frac{x + 2 + x - 12}{x - 5} = \frac{2x - 10}{x - 5} = \frac{2(x - 5)}{x - 5} = 2[/tex]
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[tex] \frac{10}{8 + x} - \frac{2 - x}{8 + x} = \frac{10 - 2 + x}{8 + x} = \frac{8 + x}{8 + x} = 1 [/tex]
[tex] \frac{x + 2}{x - 5} + \frac{x - 12}{x - 5} = \frac{x + 2 + x - 12}{x - 5} = \frac{2x - 10}{x - 5} = \frac{2(x - 5)}{x - 5} = 2[/tex]