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oralgazina97
@oralgazina97
July 2022
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tg(2x+π/6)≥-√3 решите даю 20 баллов
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Tg(2x+π/6)≥-√3
-π/3+πn ≤ 2x+π/6 < π/2+πn, n∈Z
-π/3-π/6+πn ≤ 2x < π/2-π/6+πn, n∈Z
-π/2+πn ≤ 2x < π/3+πn, n∈Z
-π/4+πn/2 ≤ x < π/6 +πn, n∈Z
x∈[-π/4+πn/2 ;
π/6 +πn), n∈Z
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Verified answer
Tg(2x+π/6)≥-√3-π/3+πn ≤ 2x+π/6 < π/2+πn, n∈Z
-π/3-π/6+πn ≤ 2x < π/2-π/6+πn, n∈Z
-π/2+πn ≤ 2x < π/3+πn, n∈Z
-π/4+πn/2 ≤ x < π/6 +πn, n∈Z
x∈[-π/4+πn/2 ; π/6 +πn), n∈Z