sin(13π/6)= sin(2π+π/6)=sinπ/6=1/2
tg(-11π/6)=-tg(11π/6)=-tg(2π-π/6)=-tg(-π/6)=tgπ/6=√3/3
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
sin(13π/6)= sin(2π+π/6)=sinπ/6=1/2
tg(-11π/6)=-tg(11π/6)=-tg(2π-π/6)=-tg(-π/6)=tgπ/6=√3/3