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pahandiy
@pahandiy
July 2022
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Cos(p/3-3x)-cos(p/6-5x)=0
p=пи
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Answers & Comments
pomoshnik09
-2sin(π/3-3x+π/6-5x)/2* sin(π/3-3x-π/6+5x)/2=0
-2sin(π/2-8x)/2 *sin(π/6+2x)/2=0
-2sin(π/4-4x)*sin(π/12+x)=0
1)sin(π/4-4x)=0 или 2) sin(π/12+x)=0
4x-π/4=πn
4x=πn-π/4
x=-π/16+πn/4
2) x+π/12=0 x=πn-π/12. n∈Z
1 votes
Thanks 1
pahandiy
Спасибо огромное!
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Answers & Comments
-2sin(π/2-8x)/2 *sin(π/6+2x)/2=0
-2sin(π/4-4x)*sin(π/12+x)=0
1)sin(π/4-4x)=0 или 2) sin(π/12+x)=0
4x-π/4=πn
4x=πn-π/4
x=-π/16+πn/4
2) x+π/12=0 x=πn-π/12. n∈Z