[tex]\displaystyle\\\frac{a}{7a-14}+\frac{1}{2-a} =-\frac{a}{7(2-a)} +\frac{1}{2-a} =\frac{7-a}{7(2-a)}[/tex]
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[tex]\displaystyle\\\frac{a}{7a-14}+\frac{1}{2-a} =-\frac{a}{7(2-a)} +\frac{1}{2-a} =\frac{7-a}{7(2-a)}[/tex]