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lylalinadina
@lylalinadina
August 2022
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найти производную функции f(x)= 2sin3x
в точках
а) х=pi/6
б)х=0
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Беня2018
F'(x)=2(cos3x)*(3x)'=6cos3x
f'(π/6)=6cos(π/6)=6√3/2=3√3
f'(0)=6cos0=6*1=6
3 votes
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klera1111
Беня
lylalinadina
Огромное спасибо
klera1111
Беня 2018
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Answers & Comments
f'(π/6)=6cos(π/6)=6√3/2=3√3
f'(0)=6cos0=6*1=6