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tanka2014
@tanka2014
July 2022
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помогите пожалуйста.. Очень надо 6^x + 1/6 ^x > 2
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sedinalana
6^x=a
(a+1)/a-2>0
(a+1-2a)/a>0
(1-a)/a>0
a=1 a=0
0<a<1
0<6^x<1
x<0
x∈(-∞;0)
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Answers & Comments
(a+1)/a-2>0
(a+1-2a)/a>0
(1-a)/a>0
a=1 a=0
0<a<1
0<6^x<1
x<0
x∈(-∞;0)