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Ответ:вот

Объяснение:

[tex]\displaystyle\bf\\1)\\\\\left \{ {{x-y=2} \atop {3x-2y=9}} \right. \\\\\\\left \{ {{y=x-2} \atop {3x-2\cdot(x-2)=9}} \right. \\\\\\\left \{ {{y=x-2} \atop {3x-2x+4=9}} \right. \\\\\\\left \{ {{y=5-2} \atop {x=5}} \right. \\\\\\\left \{ {{y=3} \atop {x=5}} \right. \\\\\\Otvet \ : \ \Big(5 \ ; \ 3\Big)\\\\\\2)\\\\\left \{ {{5x+6y=-8} \atop {7x+3y=5 \ |\cdot(-2)}} \right. \\\\\\+\left \{ {{5x+6y=-8} \atop {-14x-6y=-10}} \right. \\-----------\\-9x=-18\\\\x=2[/tex]

[tex]\displaystyle\bf\\3y=5-7x=5-7\cdot 2=5-14=-9\\\\y=-9:3=-3\\\\\\Otvet: \ \Big(2 \ ; \ -3\Big)[/tex]