Ответ:
[tex]u = 2.7v \: r1 = 5om \: r2 = 5om \\ \frac{1}{r1.2} = \frac{1}{r1} + \frac{1}{r2} = \frac{1}{5} + \frac{1}{5} = \frac{2}{5} \\ r1.2 = 2.5om \\ l = \frac{u}{r} = 2.7 \div 2.5 = 1.08 \: a[/tex]
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Ответ:
[tex]u = 2.7v \: r1 = 5om \: r2 = 5om \\ \frac{1}{r1.2} = \frac{1}{r1} + \frac{1}{r2} = \frac{1}{5} + \frac{1}{5} = \frac{2}{5} \\ r1.2 = 2.5om \\ l = \frac{u}{r} = 2.7 \div 2.5 = 1.08 \: a[/tex]