Ответ:
Объяснение:
M(CaC2) = Ar(Ca) + Ar(C) * 2 = 40 + 12 * 2 = 64
w(Ca) = Ar(Ca) * n/M(CaC2) * 100% = 40/64 * 100% = 62,5%
w(С)) = Ar(C) * n/M(CaC2) * 100% = 12 * 2/64 * 100% = 37,5%
M(NO2) = Ar(N) + Ar(O) * 2 = 14 + 16 * 2 = 46
w(N) = Ar(N) * n/M(NO2) * 100% = 14/46 * 100% = 30,43%
w(O) = Ar(O) * n/M(NO2) * 100% = 16 * 2/46 * 100% = 69,57%
M(Li2O) = Ar(Li) * 2 + Ar(O) = 7 * 2 + 16 = 30
w(Li) = Ar(Li) * n/M(Li2O) * 100% = 7 * 2/30 * 100% = 46,67%
w(O) = Ar(O) * n/M(Li2O) * 100% = 16 /30 * 100% = 53,33%
M(PH3) = Ar(P) + Ar(H) * 3 = 31 + 1 * 3 = 34
w(Р) = Ar(Р) * n/M(PH3) * 100% = 31/34 * 100% = 91,17%
w(Н) = Ar(Н) * n/M(PH3) * 100% = 1 * 3/34 * 100% = 8,83%
M(BaCl2) = Ar(Ba) + Ar(Cl) * 2 = 14 + 16 * 2 = 46
w(Ba) = Ar(Ba) * n/M(BaCl2) * 100% = 14/46 * 100% = 30,43%
w(Cl) = Ar(Cl) * n/M(BaCl2) * 100% = 16 * 2/46 * 100% = 69,57%
M(FeCl2) = Ar(Fe) + Ar(Cl) * 2 = 56 + 35 * 2 = 126
w(Fe) = Ar(Fe) * n/M(FeCl2) * 100% = 56/126 * 100% = 44,44%
w(Cl) = Ar(Cl) * n/M(FeCl2) * 100% = 35 * 2/126 * 100% = 55,56%
M(FeCl3) = Ar(Fe) + Ar(Cl) * 3 = 56 + 35 * 3 = 161
w(Fe) = Ar(Fe) * n/M(FeCl3) * 100% = 56/161 * 100% = 34,78%
w(Cl) = Ar(Cl) * n/M(FeCl3) * 100% = 35 * 3/161 * 100% = 65,22%
M(PbCl2) = Ar(Pb) + Ar(Cl) * 2 = 207 + 35 * 2 = 277
w(Pb) = Ar(Pb) * n/M(PbCl2) * 100% = 207/277 * 100% = 74,73%
w(Cl) = Ar(Cl) * n/M(PbCl2) * 100% = 35 * 2/277 * 100% =25,27%
M(Nа2O) = Ar(Nа) * 2 + Ar(O) = 23 * 2 + 16 = 62
w(Nа) = Ar(Nа) * n/M(Nа2O) * 100% = 23 * 2/62 * 100% = 71,19%
w(O) = Ar(O) * n/M(Nа2O) * 100% = 16 /62 * 100% = 25,81%
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
Объяснение:
M(CaC2) = Ar(Ca) + Ar(C) * 2 = 40 + 12 * 2 = 64
w(Ca) = Ar(Ca) * n/M(CaC2) * 100% = 40/64 * 100% = 62,5%
w(С)) = Ar(C) * n/M(CaC2) * 100% = 12 * 2/64 * 100% = 37,5%
M(NO2) = Ar(N) + Ar(O) * 2 = 14 + 16 * 2 = 46
w(N) = Ar(N) * n/M(NO2) * 100% = 14/46 * 100% = 30,43%
w(O) = Ar(O) * n/M(NO2) * 100% = 16 * 2/46 * 100% = 69,57%
M(Li2O) = Ar(Li) * 2 + Ar(O) = 7 * 2 + 16 = 30
w(Li) = Ar(Li) * n/M(Li2O) * 100% = 7 * 2/30 * 100% = 46,67%
w(O) = Ar(O) * n/M(Li2O) * 100% = 16 /30 * 100% = 53,33%
M(PH3) = Ar(P) + Ar(H) * 3 = 31 + 1 * 3 = 34
w(Р) = Ar(Р) * n/M(PH3) * 100% = 31/34 * 100% = 91,17%
w(Н) = Ar(Н) * n/M(PH3) * 100% = 1 * 3/34 * 100% = 8,83%
M(BaCl2) = Ar(Ba) + Ar(Cl) * 2 = 14 + 16 * 2 = 46
w(Ba) = Ar(Ba) * n/M(BaCl2) * 100% = 14/46 * 100% = 30,43%
w(Cl) = Ar(Cl) * n/M(BaCl2) * 100% = 16 * 2/46 * 100% = 69,57%
M(FeCl2) = Ar(Fe) + Ar(Cl) * 2 = 56 + 35 * 2 = 126
w(Fe) = Ar(Fe) * n/M(FeCl2) * 100% = 56/126 * 100% = 44,44%
w(Cl) = Ar(Cl) * n/M(FeCl2) * 100% = 35 * 2/126 * 100% = 55,56%
M(FeCl3) = Ar(Fe) + Ar(Cl) * 3 = 56 + 35 * 3 = 161
w(Fe) = Ar(Fe) * n/M(FeCl3) * 100% = 56/161 * 100% = 34,78%
w(Cl) = Ar(Cl) * n/M(FeCl3) * 100% = 35 * 3/161 * 100% = 65,22%
M(PbCl2) = Ar(Pb) + Ar(Cl) * 2 = 207 + 35 * 2 = 277
w(Pb) = Ar(Pb) * n/M(PbCl2) * 100% = 207/277 * 100% = 74,73%
w(Cl) = Ar(Cl) * n/M(PbCl2) * 100% = 35 * 2/277 * 100% =25,27%
M(Nа2O) = Ar(Nа) * 2 + Ar(O) = 23 * 2 + 16 = 62
w(Nа) = Ar(Nа) * n/M(Nа2O) * 100% = 23 * 2/62 * 100% = 71,19%
w(O) = Ar(O) * n/M(Nа2O) * 100% = 16 /62 * 100% = 25,81%