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bloom2000winxmailru
@bloom2000winxmailru
December 2021
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60 баллов умоляю плииииииз
массовая доля фосфора в H2P2O4
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DJToxa
Verified answer
Решение:
M(H2P2O4)=128г/моль
M(P)=31г/моль
w(P)=M(P)/M(H2P2O4)=31*2/128=0,4843=48,43%
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Answers & Comments
Verified answer
Решение:M(H2P2O4)=128г/моль
M(P)=31г/моль
w(P)=M(P)/M(H2P2O4)=31*2/128=0,4843=48,43%