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NariGel
@NariGel
August 2022
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Арифметическая прогрессия (аn) задана условиями: а1 = - 5, a(n+1 - внизу а) = an + 12. Найдите сумму первых шести ее членов/
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ShirokovP
Verified answer
A1 = - 5
a_n+1 = a_n + 12
d = 12
S 6 - ?
a6 = a1 + 5d = - 5 + 5*12 = 55
S6 = (a1 + a6)*3 = (- 5 + 55)*3 = 50*3 = 150
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Answers & Comments
Verified answer
A1 = - 5a_n+1 = a_n + 12
d = 12
S 6 - ?
a6 = a1 + 5d = - 5 + 5*12 = 55
S6 = (a1 + a6)*3 = (- 5 + 55)*3 = 50*3 = 150