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katyprok
@katyprok
July 2022
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а) x^3-36x=0
б) x^2-4/3 - 5x -2/6=1 решите биквадратное уравнение!
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osakara
А) x(x^2-36)=0
x=0. x^2-36 =0 x^2= +-6
б) x^2 - 8/6 - 2/6 - 5x +1 =0
x^2 - 1 + 1 - 5x = 0
x(x-5)=0
x=0. x-5=0 x=5
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Answers & Comments
x=0. x^2-36 =0 x^2= +-6
б) x^2 - 8/6 - 2/6 - 5x +1 =0
x^2 - 1 + 1 - 5x = 0
x(x-5)=0
x=0. x-5=0 x=5