1)0,027 + b³ = 0,3³ + b³ = (0,3 + b)(0,3² - 0,3b + b²) = (0,3 + b)(0,09 - 0,3b + b²)
2) 64a³ - 125 = (4a)³ - 5³ = (4a - 5)((4a)² + 4a*5 + 5²) = (4a - 5)(16a² + 20a + 25)
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Answers & Comments
1)0,027 + b³ = 0,3³ + b³ = (0,3 + b)(0,3² - 0,3b + b²) = (0,3 + b)(0,09 - 0,3b + b²)
2) 64a³ - 125 = (4a)³ - 5³ = (4a - 5)((4a)² + 4a*5 + 5²) = (4a - 5)(16a² + 20a + 25)