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SuperHenryMoore
@SuperHenryMoore
August 2021
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сравните числа (1/6)^0.2 (1/6)^1.2 8^-0.2 8^-1.2
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mymurkin
(1/6)^(0.2)>(1/6)^1.2 , т.к. функция у=(1/6)^x убывающая
8^(-0.2)>8^(-1.2), т.к.функция у=(8)^x возрастающая
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Answers & Comments
8^(-0.2)>8^(-1.2), т.к.функция у=(8)^x возрастающая