Очень надеюсь на ваш ум ❤️❤️❤️ 2sinα + √2cosα, где α=П/4 sin3α - cos2α, где α=П/6. Created by shkolnichka. algebra-ru

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$1)\; \; a=\frac{\pi}{4}:\\\\2\, sina+\sqrt2\, cosa=2\, sin\frac{\pi}{4}+\sqrt2\, cos\frac{\pi}{4}=2\cdot \frac{\sqrt2}{2}+\sqrt2\cdot \frac{\sqrt2}{2}=\sqrt2+1\\\\2)\; \; a=\frac{\pi}{6}:\\\\sin3a-cos\, 2a=sin\frac{3\pi }{6} -cos\frac{2\pi }{6}=sin\frac{\pi }{2}-cos\frac{\pi}{3}=1-\frac{1}{2}=\frac{1}{2}$

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