Verified answer

1)

[tex]3 \frac{5}{6} + a = 5 + 2 \frac{1}{6} [/tex]

[tex]3 \frac{5}{6} + a = 7 \frac{1}{6} [/tex]

[tex]a = 7 \frac{1}{6} - 3 \frac{5}{6} [/tex]

[tex]7 \frac{1}{6} - 3 \frac{5}{6} = \frac{43}{6} - \frac{23}{6} = \frac{20}{6} = \frac{10}{3} = 3 \frac{1}{3} [/tex]

[tex]a = 3 \frac{1}{3} [/tex]

2)

[tex]b + \frac{9}{13} = 8 \frac{6}{13} - 4 \frac{2}{13} [/tex]

[tex]b + \frac{9}{13} = 4 \frac{4}{13} [/tex]

[tex]b = 4 \frac{4}{13} - \frac{9}{13} [/tex]

[tex]4 \frac{4}{13} - \frac{9}{13} = \frac{56}{13} - \frac{9}{13} = \frac{47}{13} = 3 \frac{8}{13} [/tex]

[tex]b = 3 \frac{8}{13} [/tex]

Ответ:

1) а = десять третьих, или 3целые одна третья;

2) b = сорок семь тринадцатых, или 3целые восемь тринадцатых.