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Rainhard2000
@Rainhard2000
July 2022
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Помогите решить уравнение 2sin (4x+pi/6)+√3=0
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Gerren
2sin (4x+pi/6)+√3=0
2sin (4x+pi/6)=-√3/2
4x+pi/6=
2pi*n+4pi/3
4x=2pi*n+4pi/3-pi/6
x=pi*n/2+7pi/24 n
∈Z
4x+pi/6=2pi*k+5pi/3
4x=2pi*k+5pi/3-pi/6
x=pi*k/2+3pi/8 k
∈Z
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Answers & Comments
2sin (4x+pi/6)=-√3/2
4x+pi/6=2pi*n+4pi/3
4x=2pi*n+4pi/3-pi/6
x=pi*n/2+7pi/24 n∈Z
4x+pi/6=2pi*k+5pi/3
4x=2pi*k+5pi/3-pi/6
x=pi*k/2+3pi/8 k∈Z