Помогите, пожалуйста! 1) (2/3)^x * (9/8)^x=27/64 2)10^x - 5^(x-1) *2^(x-2)=950 3)5^x+5^(x+2) +5^(x+4)=651. Created by mosunovaa86. algebra-ru

64 2)10^x - 5^(x-1) *2^(x-2)=950 3)5^x+5^(x+2) +5^(x+4)=651...

July 2022 1 6 Report

Помогите, пожалуйста!
1) (2/3)^x * (9/8)^x=27/64
2)10^x - 5^(x-1) *2^(x-2)=950
3)5^x+5^(x+2) +5^(x+4)=651

Answers & Comments

Utem $( \frac{2}{3})^x*( \frac{9}{8})^x= \frac{27}{64}$
$\frac{2^x}{3^x}* \frac{3^{2x}}{2^{3x}}= \frac{3^3}{2^6}$
$\frac{3^{x}}{2^{2x}}= \frac{3^3}{2^{2*3}}$
$(\frac{3}{2^{2}})^x= (\frac{3}{2^{2}})^3$
$x=3$

10ˣ-5ˣ⁻¹*2ˣ⁻²=950
2ˣ*5ˣ-5ˣ*5⁻¹*2ˣ*2⁻²=950
2ˣ*5ˣ(1-5⁻¹*2⁻²)=950
10ˣ*(19/20)=950
10ˣ=950*20/19
10ˣ=1000
10ˣ=10³
x=3

5ˣ+5ˣ⁺²+5ˣ⁺⁴=651
5ˣ+5ˣ*5²+5ˣ*5⁴=651
5ˣ(1+25+625)=651
5ˣ*651=651
5ˣ=651:651
5ˣ=1
5ˣ=5⁰
x=0

0 votes Thanks 0

Answers & Comments

pomogite pozhalujsta ochen srochno fajl prikreplyon

3 chasa bolshe chem vtoromu za kakoe vremya prohodit rasstoyanie mezhdu a i v kazhdy

pomogite pozhalujstac802554c2c22b9bd9ed99add3385d7df 33071

huligan vova porval stengazetu na neskolko chastej prichyom kazhdyj raz on rval ka

est kucha iz 1001 kamnya odnim hodom iz kakoj nibud kuchi gde lezhit bolshe odno

reshite uravnenie 2 x3x97

рекомендуемые вопросы

Helpful Links

Helpful Social