Помогите, пожалуйста! 1) (2/3)^x * (9/8)^x=27/64 2)10^x - 5^(x-1) *2^(x-2)=950 3)5^x+5^(x+2) +5^(x+4)=651. Created by mosunovaa86. algebra-ru

64 2)10^x - 5^(x-1) *2^(x-2)=950 3)5^x+5^(x+2) +5^(x+4)=651...

July 2022 1 5 Report

Помогите, пожалуйста!
1) (2/3)^x * (9/8)^x=27/64
2)10^x - 5^(x-1) *2^(x-2)=950
3)5^x+5^(x+2) +5^(x+4)=651

Answers & Comments

Utem $( \frac{2}{3})^x*( \frac{9}{8})^x= \frac{27}{64}$
$\frac{2^x}{3^x}* \frac{3^{2x}}{2^{3x}}= \frac{3^3}{2^6}$
$\frac{3^{x}}{2^{2x}}= \frac{3^3}{2^{2*3}}$
$(\frac{3}{2^{2}})^x= (\frac{3}{2^{2}})^3$
$x=3$

10ˣ-5ˣ⁻¹*2ˣ⁻²=950
2ˣ*5ˣ-5ˣ*5⁻¹*2ˣ*2⁻²=950
2ˣ*5ˣ(1-5⁻¹*2⁻²)=950
10ˣ*(19/20)=950
10ˣ=950*20/19
10ˣ=1000
10ˣ=10³
x=3

5ˣ+5ˣ⁺²+5ˣ⁺⁴=651
5ˣ+5ˣ*5²+5ˣ*5⁴=651
5ˣ(1+25+625)=651
5ˣ*651=651
5ˣ=651:651
5ˣ=1
5ˣ=5⁰
x=0

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