Ответ:вот
Объяснение:
[tex]\displaystyle\bf\\1)\\\\64^{2} -81=64^{2} -9^{2} =(64-9)\cdot (64+9)=55\cdot 73=4015\\\\\\2)\\\\64y^{3} -0,008x^{3} =8\cdot(8y^{3} -0,001x^{3} )=8\cdot\Big[(2y)^{3}-(0,1x)^{3} } \Big]=\\\\\\=8\cdot(2y-0,1x)\cdot(4y^{2} +0,2xy+0,01x^{2} )\\\\\\3)\\\\1000+8a^{9} =8\cdot(125 +a^{9} )=8\cdot\Big[(5)^{3}+(a^{3} )^{3} } \Big]=\\\\\\=8\cdot(5+a^{3} )\cdot(25-5a^{3} +a^{6} )[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Ответ:вот
Объяснение:
[tex]\displaystyle\bf\\1)\\\\64^{2} -81=64^{2} -9^{2} =(64-9)\cdot (64+9)=55\cdot 73=4015\\\\\\2)\\\\64y^{3} -0,008x^{3} =8\cdot(8y^{3} -0,001x^{3} )=8\cdot\Big[(2y)^{3}-(0,1x)^{3} } \Big]=\\\\\\=8\cdot(2y-0,1x)\cdot(4y^{2} +0,2xy+0,01x^{2} )\\\\\\3)\\\\1000+8a^{9} =8\cdot(125 +a^{9} )=8\cdot\Big[(5)^{3}+(a^{3} )^{3} } \Big]=\\\\\\=8\cdot(5+a^{3} )\cdot(25-5a^{3} +a^{6} )[/tex]