Ответ:
[tex]2) (-1\frac{1}{3})^2-(\frac{5}{6} )^2=(-\frac{4}{3})^2-(\frac{5}{6} )^2=\frac{16}{9} -\frac{25}{36} =\frac{64-25}{36} =\frac{39}{36} =\frac{13}{12} =1\frac{1}{12} \\3) (-1,2)*(-0,4)-(1,6*0,6)=0,48-0,96=-0,48\\4)(2,8+(-3,4))*(-1,6+4,2)=(2,8-3,4)*2,6=0,6*2,6=1,56[/tex]
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Ответ:
[tex]2) (-1\frac{1}{3})^2-(\frac{5}{6} )^2=(-\frac{4}{3})^2-(\frac{5}{6} )^2=\frac{16}{9} -\frac{25}{36} =\frac{64-25}{36} =\frac{39}{36} =\frac{13}{12} =1\frac{1}{12} \\3) (-1,2)*(-0,4)-(1,6*0,6)=0,48-0,96=-0,48\\4)(2,8+(-3,4))*(-1,6+4,2)=(2,8-3,4)*2,6=0,6*2,6=1,56[/tex]
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