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Nonononono1
@Nonononono1
July 2022
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дана геометрическая прогрессия 1, 3/2, ... Найдите номер члена этой прогрессии, если равного 729/64
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sedinalana
Q=3/2:1=3/2
bn=b1*q^(n-1)
1*(3/2)^(n-1)=729/64
(3/2)^(n-1)=(/2)^6
n-1=6
n=7
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Answers & Comments
bn=b1*q^(n-1)
1*(3/2)^(n-1)=729/64
(3/2)^(n-1)=(/2)^6
n-1=6
n=7