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Ариша1993
@Ариша1993
July 2022
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(Sin (п-x)+cos (0.5п+x)cosx)/sin^2 0.5п при x=п/6
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zarembo73
(sin(
π
-x)+cos(
π/2
+x)cosx)/sin
²π/2=(sinx-sinx*cosx)/1=sinx(1-cosx)=sinπ/6(1-cosπ/6)=1/2*(1-√3/2)=1/2-√3/4.
1 votes
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