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ДженниЛенни
@ДженниЛенни
July 2022
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Найдите значение производной функции в точке x0
y = sin (2x-п/3), если x0 = п/6
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sharadi
Verified answer
Y' = 2Cos(2x - π/3)
y'(π/6) = 2Cos(2*π/6 - π/3) = 2Cos0 = 2*1 = 2
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Verified answer
Y' = 2Cos(2x - π/3)y'(π/6) = 2Cos(2*π/6 - π/3) = 2Cos0 = 2*1 = 2