Объяснение:
[tex] \frac{x ^{2} - 3x - 18 }{x - 6} = \frac{(x - 6)(x + 3)}{x - 6} = x + 3[/tex]
x - 6 ≠ 0 ㅤㅤㅤㅤㅤ x ≠ 6
x² - 3x - 18 = 0
За теоремою Вієта:
x1 + x2 = -b ㅤ x1 + x2 = 3 ㅤ x1 = -3
x1 * x2 = c ㅤ x1 * x2 = -18 ㅤ x2 = 6
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Verified answer
Объяснение:
[tex] \frac{x ^{2} - 3x - 18 }{x - 6} = \frac{(x - 6)(x + 3)}{x - 6} = x + 3[/tex]
x - 6 ≠ 0 ㅤㅤㅤㅤㅤ x ≠ 6
x² - 3x - 18 = 0
За теоремою Вієта:
x1 + x2 = -b ㅤ x1 + x2 = 3 ㅤ x1 = -3
x1 * x2 = c ㅤ x1 * x2 = -18 ㅤ x2 = 6