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tolmol
@tolmol
July 2022
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не могу решить( помогите, пожалуйста
8√3 cos 5П /12 cos п/12 sin П/6
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nKrynka
Решение
(8√3)сos(5π/12)*сos(π/2)*sin(π/6) = (4√3)*( 1/2)*(cos(5π/12 - π/12) + cos(5π/12 + π/12)) = (2√3)* (cos(4π/12 + cos(6π/12)) ( 2√3)*(cosπ/6 + cosπ/2) = 2*√3 * (1/2) = √3
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Answers & Comments
(8√3)сos(5π/12)*сos(π/2)*sin(π/6) = (4√3)*( 1/2)*(cos(5π/12 - π/12) + cos(5π/12 + π/12)) = (2√3)* (cos(4π/12 + cos(6π/12)) ( 2√3)*(cosπ/6 + cosπ/2) = 2*√3 * (1/2) = √3