Ответ:
Пошаговое объяснение:
1) (a-5)√(3/(a-5))=√((3(a-5)²)/(a-5))=√(3(a-5))
2) (a-3)√(6/(a-3))=√((6(a-3)²)/(a-3))=√(6(a-3))
3) (b-4)√(2/(4-b))=-√((2(4-b)²)/(4-b))=-√(2(4-b))
4) a≥b; (a-b)√3=√(3(a-b²)
5) (7-m)√(5/(m-7))=-√((5(m-7)²)/(m-7))=-√(5(m-7))
6) a≤b; (a-b)√7=-√(7(a-b)²)
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Verified answer
Ответ:
Пошаговое объяснение:
1) (a-5)√(3/(a-5))=√((3(a-5)²)/(a-5))=√(3(a-5))
2) (a-3)√(6/(a-3))=√((6(a-3)²)/(a-3))=√(6(a-3))
3) (b-4)√(2/(4-b))=-√((2(4-b)²)/(4-b))=-√(2(4-b))
4) a≥b; (a-b)√3=√(3(a-b²)
5) (7-m)√(5/(m-7))=-√((5(m-7)²)/(m-7))=-√(5(m-7))
6) a≤b; (a-b)√7=-√(7(a-b)²)