696 Решите уравнение: д) х(х + 1)(х – 10) = (х – 1)(х-3)(х - 5);
е) (х – 1)(х – 4)(х + 7) = x(х + 1).^2
е) (х – 1)(х – 4)(х + 7) = x(х + 1).^2
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Ответ:
х(х+1)(х-10)=(х-1)(х-3)(х-5)
х(х^2-9х-10)=(х^2-4х+3)(х-5)
х^3-9х^2-10х=х^3-9х^2+23х-15
-33х=-15
х=5:11