[tex]\displaystyle\bf\\\Big(pq\Big)^{16} :\Big(pq\Big)^{7}:\Big(pq\Big)^{3} =\Big(pq\Big)^{16-7-3} =\Big(pq\Big)^{6}[/tex]
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[tex]\displaystyle\bf\\\Big(pq\Big)^{16} :\Big(pq\Big)^{7}:\Big(pq\Big)^{3} =\Big(pq\Big)^{16-7-3} =\Big(pq\Big)^{6}[/tex]