6Cos^3 x -7cos^2 x + 1 =0 Найдите корни уравнения пожалуйста. Created by noname523468. matematika-ru

Ответ:6cos(×)³-7соs(×)²+1=0Cos(×)= t6t³-7t²+1=0t=1t= -1/3t= 1/2Cos(×)=1Cos(×)= -1/3Cos(×)= 1/2X=2kn , k € ZX= n- arccos (1/3)+2kn , k € ZX= n+ arccos (1/3)+2kn , k € ZX= n/3 +2kn , k € ZX= 5n/3 +2kn , k € ZX={2kn1,91063 + 2kn4,37255 + 2knn/3 +2kn5n/3 +2kn , k € ZПошаговое объяснение:Надеюсь правильно объяснил :)А дальше как решать?Так щас6t³-6t²-t²+t-t+1=0 ; (t-1)(6t²-t-1)=0 ; (t-1)(2t×(3t+1)×(2t-1))=0 ; (t-1)(3t+1)×(2t-1)=0 --> t-1=0 , 3t+1=0 , 2t-1=0 --> t=1 , t= -1/3 , t= 1/2 !!!Хорошо, спасибо NpНовые вопросы в Математикавсі бічні грані правильної трикутної піраміди нахилені до площини основи під кутом 60, а висота піраміди 9. знайдіть об'єм пірамідидопоможіть, будь ласкаЯк знайти значення виразу?13 мин - 1км60 мин - ?кмдопоможіть, будь ласканайдите аb если а-b=3 если а³- b³=207помогит4 пожалуйста даю 15 баллов срочноПостройте график функций и определите, чему равно значение функции при заданном значении аргумента: y=x+1, y=-3x-3допоможіть будь ласка, завтра екзамен будь ласка розпишіть по діямбо я не зовсім розуміюдаю 60 балів Поясніть як розв'язати.ПОМАГИТЕ ПЖПЖП ОЧЕНЬ СРОЧНОПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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6Cos^3 x -7cos^2 x + 1 =0 Найдите корни уравнения пожалуйста...

noname523468 @noname523468

July 2022 1 28 Report

6Cos^3 x -7cos^2 x + 1 =0
Найдите корни уравнения пожалуйста

Answers & Comments

amanzholyedil

Ответ:

6cos(×)³-7соs(×)²+1=0

Cos(×)= t

6t³-7t²+1=0

t=1

t= -1/3

t= 1/2

Cos(×)=1

Cos(×)= -1/3

Cos(×)= 1/2

X=2kn , k € Z

X= n- arccos (1/3)+2kn , k € Z

X= n+ arccos (1/3)+2kn , k € Z

X= n/3 +2kn , k € Z

X= 5n/3 +2kn , k € Z

X={2kn

1,91063 + 2kn

4,37255 + 2kn

n/3 +2kn

5n/3 +2kn , k € Z

Пошаговое объяснение:

Надеюсь правильно объяснил :)

А дальше как решать?
Так щас
6t³-6t²-t²+t-t+1=0 ; (t-1)(6t²-t-1)=0 ; (t-1)(2t×(3t+1)×(2t-1))=0 ; (t-1)(3t+1)×(2t-1)=0 -->
t-1=0 , 3t+1=0 , 2t-1=0 --> t=1 , t= -1/3 , t= 1/2 !!!
Хорошо, спасибо
Np