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July 2022
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Вычислите пожалуйста.
а) sin 5П/4
б) tg7П/6
в) cosП/6-ctgП/4
г) tg3П/4*cos3П/4+ctg(-П/6)*sinП/6
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Verified answer
A
) sin 5П/4=-√2/2
б) tg7П/6=√3/3
в) cosП/6-ctgП/4=√3/2 - 1
г) tg3П/4*cos3П/4+ctg(-П/6)*sinП/6=-1*(-√2/2)+(-√3)*1/2=-√2/2-√3/2=(√2-√3)/2
2 votes
Thanks 6
LFP
г) получится +√2/2-√3/2=(√2-√3)/2 ---ОПЕЧАТКА в знаке)))
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Answers & Comments
Verified answer
A) sin 5П/4=-√2/2б) tg7П/6=√3/3
в) cosП/6-ctgП/4=√3/2 - 1
г) tg3П/4*cos3П/4+ctg(-П/6)*sinП/6=-1*(-√2/2)+(-√3)*1/2=-√2/2-√3/2=(√2-√3)/2