Ответ:
Применяем правило нахождения неизвестного члена пропорции .
[tex]\displaystyle 1)\ \ \frac{x}{15}=\frac{1}{3}\ \ \ \Rightarrow \ \ \ x=\frac{1\cdot 15}{3}=5\\\\2)\ \ \frac{16}{x}=\frac{4}{5}\ \ \ \Rightarrow \ \ \ x=\frac{16\cdot 5}{4}=20\\\\3)\ \ \frac{0,7}{3,5}=\frac{x}{4,02}\ \ \ \Rightarrow \ \ \ x=\frac{0,7\cdot 4,02}{3,5}=0,804\\\\4)\ \ \frac{2,5}{0,38}=\frac{6,5}{x}\ \ \ \Rightarrow \ \ \ x=\frac{6,5\cdot 0,38}{2,5}=0,988[/tex]
[tex]\displaystyle 5)\ \ \frac{x}{12}=\frac{7}{10}\ \ \ \Rightarrow \ \ \ x=\frac{12\cdot 7}{10}=8,4\\\\\displaystyle 6)\ \ \frac{12}{21}=\frac{x}{14}\ \ \ \Rightarrow \ \ \ x=\frac{12\cdot 14}{21}=8\\\\7)\ \ \frac{x}{16}=\frac{9}{32}\ \ \ \Rightarrow \ \ \ x=\frac{16\cdot 9}{32}=4,5\\\\8)\ \ \frac{8}{7}=\frac{15}{x}\ \ \ \Rightarrow \ \ \ x=\frac{7\cdot 15}{8}=13,125[/tex]
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Ответ:
Применяем правило нахождения неизвестного члена пропорции .
[tex]\displaystyle 1)\ \ \frac{x}{15}=\frac{1}{3}\ \ \ \Rightarrow \ \ \ x=\frac{1\cdot 15}{3}=5\\\\2)\ \ \frac{16}{x}=\frac{4}{5}\ \ \ \Rightarrow \ \ \ x=\frac{16\cdot 5}{4}=20\\\\3)\ \ \frac{0,7}{3,5}=\frac{x}{4,02}\ \ \ \Rightarrow \ \ \ x=\frac{0,7\cdot 4,02}{3,5}=0,804\\\\4)\ \ \frac{2,5}{0,38}=\frac{6,5}{x}\ \ \ \Rightarrow \ \ \ x=\frac{6,5\cdot 0,38}{2,5}=0,988[/tex]
[tex]\displaystyle 5)\ \ \frac{x}{12}=\frac{7}{10}\ \ \ \Rightarrow \ \ \ x=\frac{12\cdot 7}{10}=8,4\\\\\displaystyle 6)\ \ \frac{12}{21}=\frac{x}{14}\ \ \ \Rightarrow \ \ \ x=\frac{12\cdot 14}{21}=8\\\\7)\ \ \frac{x}{16}=\frac{9}{32}\ \ \ \Rightarrow \ \ \ x=\frac{16\cdot 9}{32}=4,5\\\\8)\ \ \frac{8}{7}=\frac{15}{x}\ \ \ \Rightarrow \ \ \ x=\frac{7\cdot 15}{8}=13,125[/tex]