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ХОЛОДок2003
@ХОЛОДок2003
August 2022
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a) (4pq)²
б) (-a/b)⁴
в) (z-x) ³
г) (5с/6d)в пятой степени
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mb17x
А) (4pq)²=16p²q²
б) (-a/b)⁴=a⁴/b⁴
в) (z-x)³=(z-x)(z²+xz+x²)
г) (5c/6d)⁵=(5⁵c⁵)/(6⁵d⁵)=(3125c⁵)/(7776d⁵)
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Answers & Comments
б) (-a/b)⁴=a⁴/b⁴
в) (z-x)³=(z-x)(z²+xz+x²)
г) (5c/6d)⁵=(5⁵c⁵)/(6⁵d⁵)=(3125c⁵)/(7776d⁵)