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аяука2603
@аяука2603
July 2022
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-6(две из трёх c +1)+7c+5 при c=7
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zhenyaM2002
Verified answer
-6 * (2/3*с+1)+7с+5= - 12/3 *с -6 +7с +5 =
=(-4с+7с) +(-6+5)= 3*с -1 , при с =7
3*7-1=21-1=20
проверим: -6 * (2/3*7+1)+7*7+5= -6( 14/3+3/3)+49+5= - 6*(17 /3) +54=
=-2*17 +54= -34+54=20
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Verified answer
-6 * (2/3*с+1)+7с+5= - 12/3 *с -6 +7с +5 ==(-4с+7с) +(-6+5)= 3*с -1 , при с =7
3*7-1=21-1=20
проверим: -6 * (2/3*7+1)+7*7+5= -6( 14/3+3/3)+49+5= - 6*(17 /3) +54=
=-2*17 +54= -34+54=20