Вычисли cost и sint , если t равно: -(53π/6). Created by washpine. matematika-ru

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KmathX

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Пошаговое объяснение:

$\sin\Big(-\dfrac{53\pi}6\Big)=\sin\Big(\dfrac{-53\pi}6+10\pi\Big)=\sin\Big(-\dfrac{53\pi}6+\dfrac{60\pi}6\Big)=\sin\Big(\dfrac{7\pi}6\Big)=\sin\Big(\dfrac{7\pi}6\Big)=\sin\Big(\pi+\dfrac\pi6\Big)=-\sin\Big(\dfrac\pi6\Big)=-\dfrac12$

$\cos\Big(-\dfrac{53\pi}6\Big)=\cos\Big(\dfrac{53\pi}6-10\pi\Big)=\cos\Big(\dfrac{53\pi}6-\dfrac{60\pi}6\Big)=\cos\Big(-\dfrac{7\pi}6\Big)=\cos\Big(\dfrac{7\pi}6\Big)=\cos\Big(\pi+\dfrac{\pi}6\Big)=-\cos\Big(\dfrac\pi6\Big)=-\dfrac12\sqrt3$

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