Ответ: В)
[tex] \frac{ \frac{2}{3} }{ \frac{4}{9}x - \frac{4}{9} } + \frac{1}{2} = 1 \\ \frac{ \frac{2}{3} }{ \frac{4}{9}x - \frac{4}{9} } = 1 + \frac{1}{2} \\ \frac{ \frac{2}{3} }{ \frac{4}{9}x - \frac{4}{9} } = 1 \frac{1}{2} \\ \frac{4}{9}x - \frac{4}{9} = \frac{2}{3} \div 1 \frac{1}{2 } \\ \frac{4}{9}x - \frac{4}{9} = \frac{2 \times 2}{3 \times 3} \\ \frac{4}{9}x - \frac{4}{9} = \frac{4}{9} \\ \frac{4}{9} x = \frac{4}{9} + \frac{4}{9} \\ \frac{4}{9}x = \frac{8}{9} \\ x = \frac{8}{9} \div \frac{4}{9} \\ x = \frac{8 \times 9}{9 \times 4} \\ x = 2[/tex]
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Ответ: В)
[tex] \frac{ \frac{2}{3} }{ \frac{4}{9}x - \frac{4}{9} } + \frac{1}{2} = 1 \\ \frac{ \frac{2}{3} }{ \frac{4}{9}x - \frac{4}{9} } = 1 + \frac{1}{2} \\ \frac{ \frac{2}{3} }{ \frac{4}{9}x - \frac{4}{9} } = 1 \frac{1}{2} \\ \frac{4}{9}x - \frac{4}{9} = \frac{2}{3} \div 1 \frac{1}{2 } \\ \frac{4}{9}x - \frac{4}{9} = \frac{2 \times 2}{3 \times 3} \\ \frac{4}{9}x - \frac{4}{9} = \frac{4}{9} \\ \frac{4}{9} x = \frac{4}{9} + \frac{4}{9} \\ \frac{4}{9}x = \frac{8}{9} \\ x = \frac{8}{9} \div \frac{4}{9} \\ x = \frac{8 \times 9}{9 \times 4} \\ x = 2[/tex]