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aniskova31
@aniskova31
July 2022
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6sin^2 2x-sin2x-1=0
Помогите!!!!!
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sedinalana
Verified answer
6sin²2x-sin2x-1=0
sin2x=a
6a²-a-1=0
D=1+24=25
a1=(1-5)/12=-1/3⇒sin2x=-1/3⇒2x=(-1)^(n+1)*arcsin1/3+πn⇒
x=(-1)^(n+1)*1/2*arcsin1/3+πn/2,n∈z
a2=(1+5)/12=1/2⇒sinx=1/2⇒x=(-1)^n*π/6+πn⇒x=(-1)^n*π/12+πn/2,n∈z
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aniskova31
Спасибо большое!
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Answers & Comments
Verified answer
6sin²2x-sin2x-1=0sin2x=a
6a²-a-1=0
D=1+24=25
a1=(1-5)/12=-1/3⇒sin2x=-1/3⇒2x=(-1)^(n+1)*arcsin1/3+πn⇒
x=(-1)^(n+1)*1/2*arcsin1/3+πn/2,n∈z
a2=(1+5)/12=1/2⇒sinx=1/2⇒x=(-1)^n*π/6+πn⇒x=(-1)^n*π/12+πn/2,n∈z