Verified answer

[tex]\displaystyle\bf\\-6x^{2} -5x+5=0\\\\6x^{2} +5x-5=0\\\\x_{1} \cdot x_{2} =\frac{-5}{6} =-\frac{5}{6} \\\\\\Otvet: \ x_{1} \cdot x_{2}=-\frac{5}{6}[/tex]

[tex]\displaystyle\bf\\Teorema \ Vieta:\\\\ax^{2} +bx+c=0\\\\x_{1} +x_{2} =-\frac{b}{a} \\\\\\x_{1}\cdot x_{2} =\frac{c}{a}[/tex]