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damir8a
@damir8a
December 2021
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Сократите дробь (9x^2-6x+1)/(6x^2+x-1)
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mmb1
Verified answer
(9x^2-6x+1)/(6x^2+x-1)
D=36-36=0
D=1+24=25
x12=(-1+-5)/12=-1/2 1/3
(3x-1)
²/(3x-1)(2x+1)=(3x-1)/(2x+1)
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Answers & Comments
Verified answer
(9x^2-6x+1)/(6x^2+x-1)D=36-36=0
D=1+24=25
x12=(-1+-5)/12=-1/2 1/3
(3x-1)²/(3x-1)(2x+1)=(3x-1)/(2x+1)