[tex]\displaystyle\bf\\\left \{ {{6y+10x=8} \atop {10x-2y=0}} \right. \\\\\\-\left \{ {{10x+6y=8} \atop {10x-2y=0}} \right.\\---------\\6y-(-2y)=8-0\\\\6y+2y=8\\\\8y=8\\\\y=8:8=1\\\\10x=2y=2\cdot1=2\\\\x=2:10=0,2\\\\Otvet \ : \ x=0,2 \ \ ; \ \ y=1[/tex]

[tex]10x - 2y = 0 \: \: | \times ( - 1)\\ 10x + 6y = 8 \\ \\ - 10x + 2y = 0 \\ 10x + 6y = 8 \\ \\ 2y + 6y = 0 + 8 \\ 8y = 8 \\ y = 8 \div 8 \\ y = 1 \\ \\ 10x - 2 \times 1 = 0 \\ 10x = 2 \\ x = 2 \div 10 \\ x = 0.2[/tex]

Ответ: х = 0,2 ; у = 1