Ответ:

Объяснение:

(x²+2x-15)/(x³+8x²-33x)=((x+5)(x-3))/(x(x+11)(x-3))=(x+5)/(x(x+11))

1) x²+2x-15=0; D=4+60=64

x₁=(-2-8)/2=-10/2=-5

x₂=(-2+8)/2=6/2=3

x²+2x-15=(x+5)(x-3)

2) x³+8x²-33x=x(x²+8x-33)

x²+8x-33=0; D=64+132=196

x₁=(-8-14)/2=-22/2=-11

x₂=(-8+14)/2=6/2=3

x(x²+8x-33)=x(x+11)(x-3)