4у²-25=0
(2y-5)(2y+5) = 0
2y-5 = 0 или 2у+5 = 0
2у = 5 2у = - 5
у1 = 5/2 у2 = -5/2
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4у²-25=0
(2y-5)(2y+5) = 0
2y-5 = 0 или 2у+5 = 0
2у = 5 2у = - 5
у1 = 5/2 у2 = -5/2