Найдите значение аргумента, удовлетворяющие условию f '(x) = g '(x), если:
f(x) = 6/(5x -9), g(x) = 3/(7-5x).
f(x) = 6/(5x -9), g(x) = 3/(7-5x).
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f ' (x) = (6/(5x - 9 ))' = (6' (5x - 9) - 6(5x - 9)')/(5x - 9)^2 = - 30/(5x - 9)^2f ' (x) = (3/(7 - 5x ))' = (3' (7 - 5x) - 3(7 - 5x)')/(7 - 5x)^2 = 15/(7 - 5x)^2
- 30/(5x - 9)^2 = 15/(7 - 5x)^2
75x^2 - 230x + 179 = 0
D = - 800
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