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urashiryaev
@urashiryaev
July 2022
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Вычислите (5^4*49^-3)/(7^-7*25^3)
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nataevgeniy
А)(5^4·(7²)^-3)/(7^-7·(5²)³)=(5^4·(7)^-6)/((7^-7)·5^6)=(5^4·7^7)/((7^6)·5^6)=7/5²=7/25
b) (81^12·10^-7)/(10^-5·27^17)=((3^4)^12·10^5)/(10^7·(3³)^17)=(3^48·10^5)/((10^7)·3^51)=1/(10²·3³)=1/2700
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Answers & Comments
b) (81^12·10^-7)/(10^-5·27^17)=((3^4)^12·10^5)/(10^7·(3³)^17)=(3^48·10^5)/((10^7)·3^51)=1/(10²·3³)=1/2700