7 ∙ 7^n. Найдите сумму первых трёх членов прогрессии...

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Геометрическая прогрессия (bn) задана условием: bn = 6/7 ∙ 7^n. Найдите сумму первых трёх членов прогрессии.

Answers & Comments

zinaidazina $b_{n} = \frac{6}{7} * 7^{n}$
$b_{1} = \frac{6}{7}* 7^{1} = \frac{6}{7}*7=6$
$b_{2} = \frac{6}{7}*7^2=42$
$b_3= \frac{6}{7}*7^3=6*49= 294$
$b_1+b_2+b_3=6+42+294=342$
Ответ: 342.

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