Ответ: D) 0,2; -2.

Объяснение:

[tex]|-8x-5|=a^2\geq 0\ \ \ \ \ \ |2x-7|=b^2\geq 0\ \ \ \ \ \ \Rightarrow\\\\a^2=b^2\ \ \ \ \ \ \Leftrightarrow\ \ \ \ \ \ (-8x-5)^2=(2x-7)^2\\\\(-8x)^2-2*(-8x)*5+5^2=(2x)^2-2*2x*7+7^2\\\\64x^2+80x+25=4x^2-28x+49\\\\60x^2+108x-24=0\ |:12\\\\5x^2+9x-2=0\\\\5x^2+10x-x-2=0\\\\5x*(x+2)-(x+2)=0\\\\(x+2)*(5x-1)=0\\\\x+2=0\\\\x_1=-2.\\\\5x-1=0\\\\5x=1\ |:5\\\\x_2=0,2.[/tex]