Ответ:

Д

Объяснение:

[tex](ab {)}^{9} \times {(bc)}^{6} \times {(abc)}^{ - 12} = {a}^{9} \times {b}^{9} \times {b}^{6} \times {c}^{6} \times {a}^{ - 12} \times {b}^{ - 12} \times {c}^{ - 12} = {a}^{9 + ( - 12)} {b}^{9 + 6 + ( - 12)} {c}^{6 + ( - 12)} = {a}^{ - 3} {b}^{3} {c}^{ - 6} [/tex]